9u^2+8u-1=0

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Solution for 9u^2+8u-1=0 equation: 



9u^2+8u-1=0

a = 9; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·9·(-1)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$


$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-10}{2*9}=\frac{-18}{18}
=-1
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+10}{2*9}=\frac{2}{18}
=1/9
$

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